Symbol(clack:cancel)

solutions/0000_0029/0008.LargestProduct/eular_8.py

@@ -0,0 +1,79 @@
+"""
+73167176531330624919225119674426574742355349194934
+96983520312774506326239578318016984801869478851843
+85861560789112949495459501737958331952853208805511
+12540698747158523863050715693290963295227443043557
+66896648950445244523161731856403098711121722383113
+62229893423380308135336276614282806444486645238749
+30358907296290491560440772390713810515859307960866
+70172427121883998797908792274921901699720888093776
+65727333001053367881220235421809751254540594752243
+52584907711670556013604839586446706324415722155397
+53697817977846174064955149290862569321978468622482
+83972241375657056057490261407972968652414535100474
+82166370484403199890008895243450658541227588666881
+16427171479924442928230863465674813919123162824586
+17866458359124566529476545682848912883142607690042
+24219022671055626321111109370544217506941658960408
+07198403850962455444362981230987879927244284909188
+84580156166097919133875499200524063689912560717606
+05886116467109405077541002256983155200055935729725
+71636269561882670428252483600823257530420752963450
+
+Find the thirteen adjacent digits in the 1000-digit number that have the greatest product. What is the value of this product?
+"""
+
+import time
+from functools import reduce
+
+
+def timer(func):
+    def wrapper(*args, **kwargs):
+        start_time = time.time()
+        result = func(*args, **kwargs)
+        end_time = time.time()
+        print(f"{func.__name__} took {end_time - start_time:.6f} seconds to run.")
+        return result
+
+    return wrapper
+
+
+@timer
+def largest_product_in_series(series: str, n: int) -> int:
+    if n <= 0 or n > len(series):
+        return 0
+    # 转换为整数列表
+    # 移除所有空格
+    series = series.replace("\n", "")
+    series = series.replace(" ", "")
+    digits = [int(x) for x in series]
+    max_product = 0
+    # 遍历所有可能的子序列
+    for i in range(len(digits) - n + 1):
+        product = reduce(lambda x, y: x * y, digits[i : i + n])
+        max_product = max(max_product, product)
+    return max_product
+
+
+if __name__ == "__main__":
+    txt = """73167176531330624919225119674426574742355349194934
+    96983520312774506326239578318016984801869478851843
+    85861560789112949495459501737958331952853208805511
+    12540698747158523863050715693290963295227443043557
+    66896648950445244523161731856403098711121722383113
+    62229893423380308135336276614282806444486645238749
+    30358907296290491560440772390713810515859307960866
+    70172427121883998797908792274921901699720888093776
+    65727333001053367881220235421809751254540594752243
+    52584907711670556013604839586446706324415722155397
+    53697817977846174064955149290862569321978468622482
+    83972241375657056057490261407972968652414535100474
+    82166370484403199890008895243450658541227588666881
+    16427171479924442928230863465674813919123162824586
+    17866458359124566529476545682848912883142607690042
+    24219022671055626321111109370544217506941658960408
+    07198403850962455444362981230987879927244284909188
+    84580156166097919133875499200524063689912560717606
+    05886116467109405077541002256983155200055935729725
+    71636269561882670428252483600823257530420752963450"""
+    print(largest_product_in_series(txt, 13))