102 lines
2.9 KiB
Python
102 lines
2.9 KiB
Python
import time
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from collections import Counter
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from pathlib import Path
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def timer(func):
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def wrapper(*args, **kwargs):
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start_time = time.time()
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result = func(*args, **kwargs)
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end_time = time.time()
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elapsed_time = end_time - start_time
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print(f"{func.__name__} time: {elapsed_time:.6f} seconds")
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return result
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return wrapper
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# 牌面数值映射
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VAL = {
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"2": 2,
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"3": 3,
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"4": 4,
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"5": 5,
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"6": 6,
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"7": 7,
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"8": 8,
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"9": 9,
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"T": 10,
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"J": 11,
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"Q": 12,
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"K": 13,
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"A": 14,
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}
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def hand_key(cards: tuple[str, ...]) -> tuple[int, ...]:
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"""
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将一手5张牌映射为规范元组。
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元组的字典序即牌力大小,可直接用 > / < 比较。
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"""
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# 1. 提取数值并降序排列
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nums = sorted([VAL[c[0]] for c in cards], reverse=True)
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suits = {c[1] for c in cards}
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# 2. 判断同花与顺子
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is_flush = len(suits) == 1
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is_straight = len(set(nums)) == 5 and nums[0] - nums[4] == 4
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# 3. 处理 A-2-3-4-5 顺子(A作为1,5-high)
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if nums == [14, 5, 4, 3, 2]:
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is_straight = True
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nums = [5, 4, 3, 2, 1]
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# 4. 统计出现次数,并按 (次数, 牌面) 降序排列
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# 这是整个方法的数学核心:多重集的字典序
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counts = Counter(nums)
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by_count = sorted(counts.items(), key=lambda x: (x[1], x[0]), reverse=True)
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# 5. 按牌型返回规范元组
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if is_flush and is_straight:
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return (9, nums[0]) # 同花顺(皇家同花顺只是顶牌为A)
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if by_count[0][1] == 4:
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return (8, by_count[0][0], by_count[1][0]) # 四条
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if by_count[0][1] == 3 and len(by_count) == 2:
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return (7, by_count[0][0], by_count[1][0]) # 葫芦
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if is_flush:
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return (6, *nums) # 同花:比全部5张降序
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if is_straight:
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return (5, nums[0]) # 顺子:比顶牌
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if by_count[0][1] == 3:
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return (4, by_count[0][0], by_count[1][0], by_count[2][0]) # 三条
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if by_count[0][1] == 2 and len(by_count) == 3:
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return (3, by_count[0][0], by_count[1][0], by_count[2][0]) # 两对
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if by_count[0][1] == 2:
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return (
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2,
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by_count[0][0],
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by_count[1][0],
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by_count[2][0],
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by_count[3][0],
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) # 一对
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return (1, *nums) # 高牌:比全部5张降序
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def read_hands(path: Path):
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with open(path) as f:
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for line in f:
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cards = line.strip().split()
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if len(cards) == 10:
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yield tuple(cards[:5]), tuple(cards[5:])
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@timer
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def main() -> int:
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data_path = Path(__file__).parent / "0054_poker.txt"
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wins = sum(1 for p1, p2 in read_hands(data_path) if hand_key(p1) > hand_key(p2))
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return wins
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if __name__ == "__main__":
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print(main())
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