Files
SolutionEuler/solutions/0016.PowerDigitSum/eular_16.py
Sidney Zhang 48f57bd443 feat(eular_12.py):优化质数测试参数并修复组合数计算逻辑
 feat(eular_13.py):新增超大整数加法解决方案
📝 docs(eular_13.md):添加算法说明文档
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📝 docs(eular_14.md):添加性能优化说明
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📝 docs(eular_15.md):添加组合数学详细说明
 feat(eular_16.py):新增幂数字和计算功能
 feat(eular_16.hs):新增Haskell版本实现
2025-12-17 16:02:06 +08:00

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Python

"""
2^15 = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26.
What is the sum of the digits of the number 2^1000 ?
"""
def power_digit_sum(n):
return sum(int(digit) for digit in str(2**n))
def main():
print(power_digit_sum(1000))
if __name__ == "__main__":
main()